The operating resistance of a 30-watt light bulb designed for a 28-volt system is approximately what?

Study for the Basic Electricity Exam. Prepare with detailed multiple choice questions, each question includes hints and explanations. Get ready for success!

Multiple Choice

The operating resistance of a 30-watt light bulb designed for a 28-volt system is approximately what?

Explanation:
When a device is rated to operate at a certain power with a given voltage, its resistance at operating temperature can be found from P = V^2 / R, so R = V^2 / P. For a 28-volt system and a 30-watt bulb, R = 28^2 / 30 = 784 / 30 ≈ 26.1 ohms. So the operating resistance is about 26 ohms. This reflects the hot, running resistance of the filament; cold resistance is lower, but the rating uses the resistance at operating temperature. The computed value around 26 ohms is the closest match to the options.

When a device is rated to operate at a certain power with a given voltage, its resistance at operating temperature can be found from P = V^2 / R, so R = V^2 / P. For a 28-volt system and a 30-watt bulb, R = 28^2 / 30 = 784 / 30 ≈ 26.1 ohms. So the operating resistance is about 26 ohms. This reflects the hot, running resistance of the filament; cold resistance is lower, but the rating uses the resistance at operating temperature. The computed value around 26 ohms is the closest match to the options.

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